Python execute ssh command(SSH server just for remote port forwarding) and capture the output

Question

Currently, I am using this command to run the ssh server for remote port forwarding using Serveo

subprocess.call('ssh -R 80:127.0.0.1:5000 serveo.net', shell=True)

I need to extract the URL from the ssh command and assign it into a variable. Is there any way to get the output?

Have a look at this question about [capturing ssh output with python](https://stackoverflow.com/q/21443690/5476782) — Evhz, Jul 10 '19 at 14:31
@PaoloMossini **Forwarding HTTP traffic from https://subdomain.serveo.net** it will keep on running and will not stop, like python Flask — DanielSeow, Jul 10 '19 at 14:34

score -1 · Answer 1 · edited Sep 19 '19 at 18:17

-1

With the bash module:

import bash
b = bash('ls tests.py')
b.stdout 'tests.py\n'
b.stderr ''

edited Sep 19 '19 at 18:17

Das_Geek

answered Sep 19 '19 at 17:17

stef toto

1 Answers1