IntelliJ IDEA: Jump to interface implementation if there is only one implementation available

Question

I have a project where everything is done through interfaces. In most of the cases these interfaces have only one implementation.

Q: Is there a way to setup IntelliJ IDEA to automatically jump to a method implementation if there is only one implementation to the interface that I am navigating to?

Example:

MyServiceInterface service = ...;
service.doWork();

I want to navigate directly to doWork() implementation when I click on it.

In which circumstance? If you use `Ctrl+Alt+Click` on the usage of an interface method it jumps to concrete implementation (might depend on the keymap you are using) — Giacomo Alzetta, Jul 03 '19 at 12:18
Ctrl+Alt+Click on `doWork()` should take you to the concrete implementation as I said. If there is more than one it will ask you which one you want to see — Giacomo Alzetta, Jul 03 '19 at 12:21

score 2 · Answer 1 · answered Jul 03 '19 at 12:17

2

Place Cursor on the interface and pressing Ctrl + Alt + B navigate to the implementation directly If only 1 implementation is available.

answered Jul 03 '19 at 12:17

Khalid Shah

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I am sorry, the question wasn't clear enough. Added an example. – Sasha Shpota Jul 03 '19 at 12:21
@OleksandrShpota place cursor on the method `doWork()` and press `Ctrl + Alt + B` – Khalid Shah Jul 03 '19 at 12:22
Also, you can navigate to the only implementation using by Ctrl + Alt + mouse-normal-click(for Mac: Cmd key + option + mouse-normal-click). – Niki.Max Apr 19 '23 at 15:08

IntelliJ IDEA: Jump to interface implementation if there is only one implementation available

1 Answers1