How to properly connect with authentication in HiveMQ?

Question

I'm trying to connect a client to a server with simple authentication using HiveMQ. On HiveMQ Client I created a client and used the connectWith() to specify that I want to connect with simple authentication. When I inputted a username and password I get a MqttClientStateException which I left below. Am I supposed to store/configure a username and password manually on the server as I just inputted a username and password like the tutorial here:

https://hivemq.github.io/hivemq-mqtt-client/docs/mqtt_operations/connect.html#authenticationauthorization .

Code:

Mqtt5BlockingClient publisher = Mqtt5Client.builder()
    .identifier(UUID.randomUUID().toString()) // the unique identifier of the MQTT client. The ID is randomly generated between 
    .serverHost("localhost")  // the host name or IP address of the MQTT server. Kept it localhost for testing. localhost is default if not specified.
    .serverPort(1883)  // specifies the port of the server
    .addConnectedListener(context -> ClientConnectionRetreiver.printConnected("Publisher1"))         // prints a string that the client is connected
    .addDisconnectedListener(context -> ClientConnectionRetreiver.printDisconnected("Publisher1"))  // prints a string that the client is disconnected
    .buildBlocking();  // creates the client builder                
    publisher.connectWith() // connects the client
        .simpleAuth()
            .username("Username")
            .password("Password".getBytes())
            .applySimpleAuth();

Exception:

Exception in thread "SubThread1" com.hivemq.client.mqtt.exceptions.MqttClientStateException: MQTT client is not connected.
at com.hivemq.client.internal.mqtt.MqttBlockingClient.subscribe(MqttBlockingClient.java:101)
at com.hivemq.client.internal.mqtt.message.subscribe.MqttSubscribeBuilder$Send.send(MqttSubscribeBuilder.java:184)
at com.main.SubThread.run(SubThread.java:83)
at java.base/java.lang.Thread.run(Thread.java:834)

Did you configure the server to accept username and password authentication? — , Jun 25 '19 at 06:50

score 4 · Accepted Answer · answered Jun 25 '19 at 09:39

4

You forgot to send the connect message

publisher.connectWith()
        .simpleAuth()
            .username("Username")
            .password("Password".getBytes())
            .applySimpleAuth()
        .send();

If you really want to authenticate the client, you have to configure the server. With HiveMQ you could use the File Role based Access Control Extension (https://www.hivemq.com/extension/file-rbac-extension/) for a simple authentication.

answered Jun 25 '19 at 09:39

SgtSilvio

476
2
5

I download the extension and it says to put it into the "extension folder" but there a 7 different extension folders in HiveMQ Community Edition. It says ". Unzip the file: `hivemq-file-rbac-extension--distribution.zip` to the directory: `/extensions`". So should I make an extensions folder in the home directory? – Chigozie A. Jun 25 '19 at 13:32
What hashing algorithm (and bit length) is being used to generate the passwords with the built in tool. If I wanted to use a different hashing algorithm could I? – Chigozie A. Jun 25 '19 at 14:04
2

You have to place the extension in the `extensions` folder inside the HiveMQ home directory. If you download the official package `hivemq-ce-2019.1.zip` from https://github.com/hivemq/hivemq-community-edition/releases and unzip it there is already an `extensions` folder created. – SgtSilvio Jun 25 '19 at 18:19

How to properly connect with authentication in HiveMQ?

1 Answers1