Compare array items (items are arrays) if items in same position are equals

Question

I'm using Adobe ExtendScript Toolkit to debug. I'm coding for InDesign and really don't have deep JavaScript knowledge (and don't know what ES6 means). ExtendScript doesn't accept let as reserved word. Maybe something about this ES6 you're meaning?

I need to compare all the items in an array and join some of them if one of its child are the same. Let me explain:

Based on the following array:

var array = [[1,"luis"] , [2,"felipe"] , [2,"erick"] , [2,"mark"] , [3,"dustin"]]

So, I want to get as result this array:

var array = [[1,"luis"] , [2,"felipe; erick; mark"] , [3,"dustin"]]

How can I compare the array items to get the desired result?

I already tried two for loops and a while. Maybe I made them wrong. Because of that, I'm here to ask you guys.

If I use this:

for (var i=0; i<array.length-1; i++) {
    for (var j=i+1; j<array.length; j++) {
        if (array[i][0] == array[j][0]) {
            array[i][1] = array[i][1] + "; " + array[j][1];
            }
        }
    }

I have all results. Like this:

1,luis
2,felipe; erick; mark
2,erick; mark
2,mark
3,dustin

score 1 · Answer 1 · answered Jun 16 '19 at 06:31

Use Object.entries and reduce.

var array = [[1,"luis"] , [2,"felipe"] , [2,"erick"] , [2,"mark"] , [3,"dustin"]];
const res = Object.entries(array.reduce((a, [n, s]) => (a[n] = a[n] ? a[n] + "; " + s : s, a), {}));
console.log(res);

.as-console-wrapper { max-height: 100% !important; top: auto; }

xianshenglu · Answer 2 · 2019-06-16T06:16:10.310

0

You can use reduce

var array = [
  [1, "luis"],
  [2, "felipe"],
  [2, "erick"],
  [2, "mark"],
  [3, "dustin"]
]
const result = array.reduce(function(re, arr) {
  const item = re.find(function(o) {
    return o[0] === arr[0]
  })
  typeof item === 'undefined' ? re.push(arr) : (item[1] = item[1] + ';' + arr[1])
  return re
}, [])
console.log(result)

edited Jun 16 '19 at 06:16

answered Jun 16 '19 at 05:57

xianshenglu

4,943
3
17
34

I'm using this code in Adobe ExtendScript Toolkit. Your snippet doesn't work for me. – Luis Felipe Corullón Jun 16 '19 at 06:08

score 0 · Answer 3 · answered Jun 16 '19 at 05:59

0

You can use Object.entries() and Array's .reduce() methods to get the desired output:

const data = [[1,"luis"] , [2,"felipe"] , [2,"erick"] , [2,"mark"] , [3,"dustin"]];

const result = Object.entries(data.reduce((r, [key, val]) => {
  r[key] = key in r ? [r[key].toString() + "; " + val] : val;
  return r;
}, {}));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Jun 16 '19 at 05:59

Mohammad Usman

37,952
20
92
95

I'm using this code in Adobe ExtendScript Toolkit. Your snippet doesn't work for me. – Luis Felipe Corullón Jun 16 '19 at 06:08

score 0 · Answer 4 · answered Jun 16 '19 at 06:02

0

You can use reduce and map

First group by first element in subarray
map entries to desired format

var array = [[1,"luis"] , [2,"felipe"] , [2,"erick"] , [2,"mark"] , [3,"dustin"]]

let op = array.reduce((op,inp)=>{
  op[inp[0]] = op[inp[0]] || []
  op[inp[0]].push(inp[1])
  return op
},{})

let final = Object.entries(op).map(([key,value])=> [+key,value.join('; ')])

console.log(final)

answered Jun 16 '19 at 06:02

Code Maniac

37,143
5
39
60

I'm using this code in Adobe ExtendScript Toolkit. Your snippet doesn't work for me. – Luis Felipe Corullón Jun 16 '19 at 06:08
@LuisFelipeCorullón it this toolkit doesn't support `ES6` and beyond then you can use [Babel](https://babeljs.io/repl) to transpile this code to `ES5` – Code Maniac Jun 16 '19 at 06:13
ESTK is saying I need a ```;``` after op – Luis Felipe Corullón Jun 16 '19 at 06:13
Babel code doesn't work too. Now, ESTK says me array.reduce is not a function. – Luis Felipe Corullón Jun 16 '19 at 06:17

score 0 · Answer 5 · answered Jun 16 '19 at 07:34

Here is the solution below

var array = [[1,"luis"] , [2,"felipe"] , [2,"erick"] , [2,"mark"] , [3,"dustin"]]

function mergeArrayBySameId(){
  let old = [];
  let mergedArr = [];
  array.map(function(curr, i){
    let tmp = "";
    let current = array[i];
    let prev    = ( i === 0 ) ? [] : array[i-1];

    if( current[0] === prev[0] ){
       tmp    = current[0];
       mergedArr[0] = tmp;

       if( !mergedArr.includes( prev[1] ) ){
          mergedArr.push( prev[1] );
       }

       mergedArr.push( current[1] );

    }
    old = prev;

  });

  let mergedStr = ""
  let mergedArrId = mergedArr[0];
  mergedArr.map(function(val){
     if( typeof val !== 'number' ){
          mergedStr += val + "; ";
     }
  });
  mergedArr = [];
  mergedArr[0] = mergedArrId;
  mergedArr[1] = mergedStr;

  function checkId(id){
    return mergedArr[0] != id[0];
  }

  let filterArray = array.filter(checkId);
  let finalArray = filterArray.concat([mergedArr]).sort();
  
  return finalArray;
}

console.log( mergeArrayBySameId() );

score 0 · Answer 6 · answered Jun 16 '19 at 08:29

Thank you all for your suggestions. I'm sorry because I'm very beginner and just have familiarity with javascript while coding for Adobe software automation. I found a way using:

var array = [[1,"luis"] , [2,"felipe"] , [2,"erick"] , [2,"mark"] , [3,"dustin"]];
for (var i=0; i<array.length-1; i++) {
    var j = i+1;
    while (j < array.length) {
        if (array[i][0] == array[j][0]) {
            array[i][1] = array[i][1] + "; " + array[j][1];
            array.splice(j , 1);
            j = i;
            }
        j++;
        }
    }
alert(array.join("\r"));

score 0 · Answer 7 · answered Jun 16 '19 at 11:53

let arr = [
    [1, "luis"],
    [3, "felipe"],
    [2, "erick"],
    [3, "mark"],
    [3, "dustin"]
];

let res = arr.reduce((acc,cur) => {
    const item = acc.find((obj) => {
        if(obj[0] === cur[0]){
            obj.push(cur[1]);
            return obj
        }
    });
    if(!item)
        acc.push(cur);
    return acc
},[]);

Compare array items (items are arrays) if items in same position are equals

7 Answers7