Display a word if it's greater and another one if it's less than

Question

Given the following PHP code, how can I display the word problems if the number is greater than one and how can I display the word problem if the output of the variable is 1 or 0?

echo "$number problems";

Answer 1

I would recommending an if-else check where the "condition" does a check against the value of $number using some comparison operator.

https://www.w3schools.com/php/php_if_else.asp

if (condition) {
    code to be executed if condition is true;
} else {
    code to be executed if condition is false;
}

You could also use a ternary https://davidwalsh.name/php-shorthand-if-else-ternary-operators

Answer 2

If you are going to be using this frequently, just make a pluralize function so you don’t repeat yourself:

function pluralize($count, $word) {
  return $count . ‘ ‘ . $word . ($count!=1 ? ‘s’ : ‘’);
}

// usage:
echo pluralize($number, ‘problem’);

The magic is in the ternary operator: if the count does not equal one, add an ‘s’

Answer 3

$var = 1;
if($var > 1){
echo "Greater";
} else {
echo "Less";
}