java GMT datetimeparse

Question

I have a string like the following

Fri May 31 2019 05:08:40 GMT-0700 (PDT)

I want to convert this to something like yyyy-MM-dd.

I tried this.

String date1 = "Fri May 31 2019 05:08:40 GMT-0700 (PDT)";
DateTimeFormatter f = DateTimeFormatter.ofPattern( "E MMM dd HH:mm:ss z uuuu" ).withLocale( Locale.US );

ZonedDateTime zdt = ZonedDateTime.parse( date1 , f );
LocalDate ld = zdt.toLocalDate();
DateTimeFormatter fLocalDate = DateTimeFormatter.ofPattern( "yyyy-MM-dd" );
String output = ld.format( fLocalDate ) ;

I am getting the error:

Exception in thread "main" java.time.format.DateTimeParseException: Text 
'Fri May 31 2019 05:08:40 GMT-0700 (PDT)' could not be parsed at index 13
at java.time.format.DateTimeFormatter.parseResolved0(Unknown Source)
at java.time.format.DateTimeFormatter.parse(Unknown Source)
at java.time.ZonedDateTime.parse(Unknown Source)

The pattern of your `DateTimeFormatter` doesn't fit the format of your string. — MrPromethee, Jun 06 '19 at 12:13
Can you tell me the exact pattern which will convert the Date in GMT format to IST — AnanR, Jun 06 '19 at 12:19
As an aside your way of formatting into `yyyy-MM-dd` is overly complicated. You just need `String output = zdt.format(DateTimeFormatter.ISO_LOCAL_DATE);`. — Ole V.V., Jun 06 '19 at 14:34

Januson · Accepted Answer · 2019-06-06T12:27:14.530

1

The patter of your formater is wrong. Year is missing ("yyyy") and timezone is not matching. To match it you need to use both z and Z you also need to add unmatched text for GMT, like "'GMT'Z (z)".

Try this:

"E MMM dd yyyy HH:mm:ss 'GMT'Z (z)"

edited Jun 06 '19 at 12:27

answered Jun 06 '19 at 12:20

Januson

4,533
34
42

score 1 · Answer 2 · answered Jun 06 '19 at 12:26

As you can see here you can use following pattern:

public static void main(String[] args) throws Exception {
    String date1 = "Fri May 31 2019 05:08:40 GMT-0700 (PDT)";
    DateTimeFormatter f = DateTimeFormatter.ofPattern( "EEE MMM dd yyyy HH:mm:ss 'GMT'Z '('z')'" ).withLocale( Locale.US );

    ZonedDateTime zdt = ZonedDateTime.parse( date1 , f );
    LocalDate ld = zdt.toLocalDate();
    DateTimeFormatter fLocalDate = DateTimeFormatter.ofPattern( "yyyy-MM-dd" );
    String output = ld.format( fLocalDate ) ;
    System.out.println(output);
}

Output:

2019-05-31

score -1 · Answer 3 · answered Jun 06 '19 at 12:27

-1

Since you need only yyyy-MM-dd formatted date, try this code:

   String date1 = "Fri May 31 2019 05:08:40 GMT-0700";

   //this format is good enough to read required data from your String
   DateFormat df1 = new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss");

   //format you require as final output
   DateFormat df2 = new SimpleDateFormat("yyyy-MM-dd");

   //convert String to date ( with required attributes ) and then format to target
   System.out.println(df2.format(df1.parse(date1)));

answered Jun 06 '19 at 12:27

TechFree

2,600
1
17
18

When java.time, the modern Java date and time API is asked about, please don’t bring on the long outdated and notoriously troublesome `SimpleDateFormat` class. – Ole V.V. Jun 06 '19 at 14:30
Thanks @Ole. Query was about converting String to the target format. The logic I put would work though. I think I missed something.. – TechFree Jun 06 '19 at 14:33
It’s not that your answer isn’t correct. I believe it is. It’s just poor advice (the tag also seems to suggest that the questioner wants to use `ZonedDateTime`, as s/he already tries, and which is a good idea). – Ole V.V. Jun 06 '19 at 14:36

java GMT datetimeparse

3 Answers3