How to use NSLock in a function?

Asked May 27 '19 at 21:38

Active May 27 '19 at 21:55

Viewed 345 times

Is this the correct method to prevent more than one thread to access the function MyTaskF?

.h file:

@interface MyInterface  : NSObject {

//... some other stuff here

}

.m file:

static NSLock *mytaskMutex;

static MyInterface *MyInterfaceSingleton;

int MyTaskF(int iVar)
{

    [mytaskMutex lock];

    //do stuff in here

    [mytaskMutex unlock];

    return 0;
}

edited May 27 '19 at 21:55

Gino Mempin

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asked May 27 '19 at 21:38

smartie1

1

You never initialize `mytaskMutex` so the calls to `lock` and `unlock` won't be made. – rmaddy May 27 '19 at 22:13
with the way the code is written, how to go initializing it the proper way?.thanks. – smartie1 May 28 '19 at 01:05
One way is to assign a value to `mytaskMutex` inside the `+ (void)initialize` method of the class. – rmaddy May 28 '19 at 01:08
will this do it? static NSLock * mytaskMutex = [[NSLock alloc] init]; How about using @synchronized method or dispatch method?. Performance wise the same?. – smartie1 May 28 '19 at 01:11
Did you try it? Did it work? – rmaddy May 28 '19 at 01:16
I think , the code is in the right direction. Thanks for the comment. If you a code suggestion, let me know. – smartie1 May 28 '19 at 01:32

How to use NSLock in a function?

0 Answers0