Regular Expression for string with any type of case variation

Question

I am trying to find a solution for a regex pattern, that is needed to determine if a word is matching the pattern, but for any variation of it.

For example: The pattern needs to match: "phone", but it also needs to match: "Phone", "PHONE", "pHone", "phOne", etc. So it shouldn't matter the type of case for any position in that string.

Is that possible in regex? Thanks for your time!

See https://stackoverflow.com/questions/9655164/regex-ignore-case-sensitivity for examples. — Irfan434, May 24 '19 at 16:15
this doesn't seem to work for my regex engine, I wish it would. — nw5280, May 24 '19 at 16:50

score 2 · Accepted Answer · answered May 24 '19 at 16:13

2

In plain regex, you can do:

[Pp][Hh][Oo][Nn][Ee]

If you are using a programming language, it might be simpler to test if string.lower() == "phone".

answered May 24 '19 at 16:13

Irfan434

1,463
14
19

Thank you! I think that's what I need! – nw5280 May 24 '19 at 16:20

Regular Expression for string with any type of case variation

1 Answers1