How to write a full property that is nullable

Question

Sorry if it is a duplicate question, I can't find it...
I want to write out a property, but still keep it nullable.

I want

public foo?: string;

to be (but nullable)

  private _foo: string;
  public get foo(): string {
    return this._foo;
  }
  public set foo(v: string) {
    // some logic with 'v'...
    this._foo = v;
  }

Where do I put my ? or is there another way?
I tried with Nullable<string> but it doesn't work either.

R3tep · Accepted Answer · 2019-05-24T08:36:36.877

2

You can write

private _foo: string|null;
public get foo(): string|null {
  return this._foo;
}
public set foo(v: string|null) {
  this._foo = v;
}

edited May 24 '19 at 08:36

answered May 24 '19 at 08:34

R3tep

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I still get the error that when I declare the object, the Property 'foo' is missing in type ' {...}'. – Hypenate May 24 '19 at 08:42
You need to set `?` into your interface – R3tep May 24 '19 at 08:44

How to write a full property that is nullable

1 Answers1