Your expression is pretty close. We might just want to have =» as a left boundary, then collect our digits with a ([0-9]+) and that would likely work:
=»([0-9]+)
RegEx
If this expression wasn't desired, it can be modified or changed in regex101.com.
RegEx Circuit
jex.im visualizes regular expressions:
Test
using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"=»([0-9]+)";
string input = @"> login as: LOGIN SERVER@00.00.00.000's password: Last login: Thu May 23
> 15:51:49 2019 from 00.00.00.000 CREER AUTANT DE REPERTOIRES SOUS
> /NAME/NAME/NAME QU'IL Y A DE COMMERCANTS GERES. LE NOM DOIT ETRE LE NO
> DE COMMERCANT. CREER ENSUITE SOUS CHACUN D'EUX UN REPERTOIRE NAME/
> <SERVER>ps -fu NAME | grep exe | echo «resultat=»`wc -l` «resultat=»14
> <SERVER>";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Demo
const regex = /=»([0-9]+)/gm;
const str = `> login as: LOGIN SERVER@00.00.00.000's password: Last login: Thu May 23
> 15:51:49 2019 from 00.00.00.000 CREER AUTANT DE REPERTOIRES SOUS
> /NAME/NAME/NAME QU'IL Y A DE COMMERCANTS GERES. LE NOM DOIT ETRE LE NO
> DE COMMERCANT. CREER ENSUITE SOUS CHACUN D'EUX UN REPERTOIRE NAME/
> <SERVER>ps -fu NAME | grep exe | echo «resultat=»\`wc -l\` «resultat=»14
> <SERVER>`;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
