RxAlamofire make post call with json body

Question

I want to make post call using RxAlamofire not able to find any method to do so

tried using requestJSON method but there is no paramter to pass post json in

 RxAlamofire.requestJSON(.post, url)

how to make post call and pass json data to post call in RxAlamofire

Look into [this](https://github.com/RxSwiftCommunity/RxAlamofire/blob/master/Sources/RxAlamofire.swift) to find all the methods. — Kamran, May 21 '19 at 06:48
unable to find how to pass post json. Which parameter as dictionary or json string not clear — alphanso, May 21 '19 at 06:53
you may want to put the JSON string in parameters? like request(...,parameters: ["json_str": yourJsonString],...) — Ming Chu, May 25 '19 at 15:04

score 1 · Accepted Answer · answered May 26 '19 at 08:59

Use following code

  var request = URLRequest(url: URL(string: "https://some_url")!)
    //Following code to pass post json 
    request.httpBody = json
    request.httpMethod = "POST"
    request.setValue("application/json", forHTTPHeaderField: "Content-Type")
    RxAlamofire.request(request as URLRequestConvertible).responseJSON().asObservable()

score 0 · Answer 2 · answered May 21 '19 at 06:48

0

use this function with proper parameters ancoding

public func urlRequest(_ method: Alamofire.HTTPMethod,
                   _ url: URLConvertible,
                   parameters: [String: Any]? = nil,
                   encoding: ParameterEncoding = URLEncoding.default,
                   headers: [String: String]? = nil)

answered May 21 '19 at 06:48

mkowal87

596
4
19

where to pass post json? – alphanso May 21 '19 at 06:50
@alphanso this should help you https://github.com/Alamofire/Alamofire/blob/master/Documentation/Usage.md#parameter-encoding – mkowal87 May 21 '19 at 09:46

Songzhw · Answer 3 · 2022-05-07T01:32:32.113

amodkanthe's solution works. But its return value is not friendly. So I changed it a litte bit

    var request = URLRequest(url: URL(string: "https://some_url")!)
    request.httpBody = jsonData  // jsonData is a Data type
    request.httpMethod = "POST"
    request.setValue("application/json", forHTTPHeaderField: "Content-Type") // this line is important
    RxAlamofire.requestJSON() //=> returns a Observable<(HttpURLResponse, Any)>, the `Any` type is actually a dictionary

p.s. the version I'm using is RxAlamofire(6.1.1)

score -1 · Answer 4 · answered Aug 19 '20 at 07:08

-1

Using jsonEncoding

RxAlamofire.requestJSON(.post, url, encode: JsonEncoding.default)

It works for me~

answered Aug 19 '20 at 07:08

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RxAlamofire make post call with json body

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