Why is my output different when the code is same?

Question

I am currently putting together a band-pass filter using the following code: https://ipython-books.github.io/116-applying-digital-filters-to-speech-sounds/

I made few edits to the above code, namely the file is no longer pulled from an url but instead from a local WAV file. Here are the associated edits

def speak(voice):
    audio = pydub.AudioSegment.from_wav(BytesIO(voice))    

    with tempfile.temporaryfile() as fn:
        wavef = audio.export(fn, format='wav')
        wavef.seek(0)                            
        wave = wavef.read()
...

voice = open("C:\\Users\\tkim1\\Documents\\librosa\\NEUT 41s 
shaking_gold.wav", "rb").read

Currently the "audio = pydub.AudioSegment.from_wav" line of the code outputs the following error: a bytes-like object is required, not 'builtin_function_or_method." I have gone over the two scripts line by line and cannot determine why this error is surfacing. Thank you so much for reading everyone. Any insights would be greatly appreciated!

If you "made a few edits", then the code isn't "the same" as your title suggests. — lurker, May 20 '19 at 20:20

score 2 · Accepted Answer · answered May 20 '19 at 20:13

2

You didn't call read, which is a method.

voice = open("...", "rb").read()
#                             ^

answered May 20 '19 at 20:13

Daniel Roseman

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thank you for the help Daniel. I am still new to coding and am making elementary mistakes. – PaperRockBazooka May 20 '19 at 20:15

Why is my output different when the code is same?

1 Answers1