RxAlmofire pass parameters to requestJSON [:]

Question

Following is method provided by RxAlamofire for making requestJSON request there is no method to pass parameters [String : String]

RxAlamofire.requestJSON(.get, url)
        .subscribe(onNext: { [weak self] (r, json) in
            if let jsonResult = JSON(json) as? JSON {
                if let foodMenuResult = MenuResult(jsonResult) as? MenuResult {
                    self?.delegate?.showMenu(menuResult: foodMenuResult)
                }
            }

            }, onError: {  [weak self] (error) in
                self?.delegate?.onError()
            },onCompleted: {})
        .disposed(by: disposeBag)

How to pass parameters to RxAlamofire requestJSON method

Yes how to add query string parameters to url when using rxalmofire — amodkanthe, May 16 '19 at 16:49

score 1 · Accepted Answer · answered May 16 '19 at 17:43

You need to construct the URL from URLComponents.

var components = URLComponents(string: "https://www.example.com/path")!
components.queryItems = [
    .init(name: "param1", value: "value1"),
    .init(name: "param2", value: "value2"),
]

let url = components.url!

The url above will be

https://www.example.com/path?param1=value1&param2=value2

The use of ! should not be problematic above as the data you are passing should be valid. Please refer to the documentation of these methods though to assess the requirement for proper nil handling.

RxAlmofire pass parameters to requestJSON [:]

1 Answers1