I'm trying to customize the authentication that comes by default in Django with a table of Mysql already made (collaborators).
When I want to register a user (with the command python manage.py createsuperuser
) I get the following error:
django.db.utils.OperationalError: (1054, "Unknown column 'collaborators.password' in 'field list'").
That error mentions that the password column does not exist, and indeed I do not have it in the table, is there any way to indicate that the password is obtained from a column called contrasena_general
?
I attach my code.
models.py
class MyUserManager(BaseUserManager):
use_in_migrations = True
def create_superuser(self, no_colaborador, nombres_colaborador, apellido_paterno_colaborador, apellido_materno_colaborador,
id_plantel, id_area_colaborador, no_empleado_sup, contrasena_general, empleado_interno):
user = self.model(no_colaborador = no_colaborador, nombres_colaborador = nombres_colaborador,
apellido_paterno_colaborador = apellido_paterno_colaborador, apellido_materno_colaborador = apellido_materno_colaborador,
id_plantel = id_plantel, id_area_colaborador = id_area_colaborador, no_empleado_sup = no_empleado_sup,
contrasena_general = contrasena_general, empleado_interno = empleado_interno,)
user.set_password(contrasena_general)
user.save(using=self._db)
return user
class Colaboradores(AbstractBaseUser):
no_colaborador = models.IntegerField(primary_key=True)
nombres_colaborador = models.CharField(max_length=150)
apellido_paterno_colaborador = models.CharField(max_length=150)
apellido_materno_colaborador = models.CharField(max_length=150)
id_plantel = models.IntegerField()
id_area_colaborador = models.IntegerField()
id_centro_costos = models.IntegerField()
no_empleado_sup = models.IntegerField()
contrasena_general = models.CharField(max_length=100)
empleado_interno = models.CharField(max_length=10)
objects = MyUserManager()
USERNAME_FIELD = "no_colaborador"
class Meta:
managed = False
db_table = 'collaborators'
app_label = "journal"
def __str__ (self):
return self.email
def def_full_name (self):
return self.nombres_colaborador
def has_perm(self, perm, obj=None):
return self.no_colaborador
def has_module_perms(self, app_label):
return self.no_colaborador
# backends.py
class MyAuthBackend(object):
def authenticate(self, no_colaborador, contrasena_general):
try:
user = Colaboradores.objects.get(no_colaborador=no_colaborador)
if user.check_password(contrasena_general):
return user
else:
return None
except Colaboradores.DoesNotExist:
logging.getLogger("error_logger").error("user with login %s does not exists " % login)
return None
except Exception as e:
logging.getLogger("error_logger").error(repr(e))
return None
def get_user(self, no_colaborador):
try:
user = Colaboradores.objects.get(no_colaborador=no_colaborador)
if user.is_active:
return user
return None
except Colaboradores.DoesNotExist:
logging.getLogger("error_logger").error("user with %(no_colaborador)d not found")
return None
# setting.py
...
AUTH_USER_MODEL = 'journal.Colaboradores'
AUTHENTICATION_BACKENDS = ('clientes.backends.MyAuthBackend', 'django.contrib.auth.backends.ModelBackend',)
How could you indicate that the password is obtained from a column in the table that is not called a password?