RegEx for matching square bracketed words with no parenthesis following

Question

I'd like to extend the syntax of Markdown with a simple pre-processing option.

When the text contains some words in squared brackets, but no parenthesis follows it:

Example text with [some reference] to show.

I'd like to extend it so that it becomes a self-referencing link:

Example text with [some reference](some-reference.html) to show.

Creating the result itself is something I can do on my own, but I have no idea, how can I match exactly only these expressions:

A word [and more] in the text.                    // this matches
A word [and more](stackoverflow.com) in the text. // this doesn't

@shadoe2020 both seems to work the way I intended to, thank you very much! — Zoltán Schmidt, May 07 '19 at 20:31
Would you mind if I post as an answer and you can select it since it worked for you? — shadow2020, May 07 '19 at 20:32

score 2 · Answer 1 · answered May 07 '19 at 20:33

2

\[(.*?)\] for your first, and for your 2nd \]\((.*?)\)

answered May 07 '19 at 20:33

shadow2020

score 1 · Accepted Answer · answered May 07 '19 at 20:40

1

Something like this

\[([^\[\]]*)\](?!\([^()]*\))

answered May 07 '19 at 20:40

2 Answers2