Unzip only files that start with a certain word

Question

I have a zip archive (let's call it archive) and let's say I want to go through some directories and finally extract ONLY the files that start with the word 'word'. Some thing similar to:

archive.zip/dir1/dir2/word***.csv

What is the command that could do this without having to extract the whole file (very big file)?

I tried this command line:

unzip -p archive.zip dir1/dir2/word***1.csv >destination

But this only extracts one file not all files that start with 'word'

Check [this](https://unix.stackexchange.com/a/14125/25919) please. — sjsam, May 02 '19 at 14:34
It helped extract a specific file. I want to extract all files that start with 'word'. There are many. I updated the question accordingly — mobelahcen, May 02 '19 at 14:59
On Linux I would put the wildcard expression to match the file in quotes. So something like this **unzip "\*/word\*.csv"** — pmqs, May 02 '19 at 15:11

sjsam · Answer 1 · 2019-05-02T15:30:36.197

2

You should do

unzip -p archive.zip dir1/dir2/word*1.csv >>destination.csv

The > truncates file destination.csv to zero length giving you the impression that only one file was unzipped, while >> creates the file if not present, otherwise appends to it which is the required behavior.

_{Reference : Check I/O redirection}

edited May 02 '19 at 15:30

answered May 02 '19 at 15:24

sjsam

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how do extract them in a directory? I get `Acess denied` even though I have full control permissions – mobelahcen May 03 '19 at 07:42

Unzip only files that start with a certain word

1 Answers1