Concatenate 0's bits of custom length with a uint8_t array

Asked May 02 '19 at 05:03

Active May 28 '19 at 07:46

Viewed 42 times

I try to concatenate some bits with the array of type uint8_t in c,as:

int main(int argc, char **argv) {
    if(argc < 2) {
        printf("Usage: %s <Input _message>\n", argv[0]);
        return -1;
    }
     uint8_t L_length_of_message =strlen(argv[1]);
     num_0's_in_bits_addedd=13; // try to || 13 bit with array
     uint8_t msg[L_length_of_message]; 
//assume this msg is already converted in hex format

Now i,e msg=0xabcf123; and i want concatenate 13(bits) with msg i,e;

  msg=0xabcf123;
  msg_in_bits=1010101111001111000100100011
  zeors_added_in_bits=0000000000000;
  new_msg_in_bits=10101011110011110001001000110000000000000;
  new_msg=0x1579e246000

The major problem is the message is stored into a char array, so shift operation for multiple bits is not working. suggest some solution for the problem??

edited May 28 '19 at 07:46

AR.5

asked May 02 '19 at 05:03

abbasi_ahsan

1

Do you want the result as unsigned integer, as hex string or as array of bits? It's not clear from your pseudocode. – M Oehm May 02 '19 at 06:28
1

@user202729 VLA have been C standard for 20 years... – Lundin May 02 '19 at 06:28
i want array of bits as out put. – abbasi_ahsan May 02 '19 at 10:06

Concatenate 0's bits of custom length with a uint8_t array

0 Answers0