How to find Exact String match using Lambda function while comparing frozen sets?

Question

While following this answer by @adrtam. I tried to find exact match for line using

A)

print(rules[rules["antecedents"].apply(lambda x: 'line' in x)])

and

B)

print(rules[rules["antecedents"].apply(lambda x: 'line' == x)])

C)

print(rules[rules["antecedents"].apply(lambda x: 'line' == str(x))])

A returns the same result of

print(rules[rules["antecedents"].apply(lambda x: 'line' in str(x))])

B and C returns an empty dataframe. I want to print rows with only exact match (not contains). How do I do this with lambda function?

P.S. Posting as a question because I don't have enough reputation to comment.

use if condition `print(rules[rules["antecedents"].apply(lambda x: if('line' == x))])` or else use `print(rules[rules["antecedents"] == 'line'])` — Nihal, Apr 24 '19 at 07:38
Why do you want to 'do this with lambda function'? As answer by @jezrael suggests, why not just use that? — Yash Nag, Apr 24 '19 at 07:40

score 3 · Accepted Answer · edited Apr 24 '19 at 07:57

3

I believe you need compare by frozenset:

print(rules[rules["antecedents"] == frozenset(['line'])])

edited Apr 24 '19 at 07:57

raakshasan

answered Apr 24 '19 at 07:37

jezrael

1

Yes exactly what I needed. Thanks. – raakshasan Apr 24 '19 at 07:40
I get ValueError: "frozenset" is not a supported function – Geoffrey Anderson Jan 14 '22 at 02:39

1 Answers1