Find element exists in first array and not in second for dynamic arrays

Question

I have two arrays and the second array is like the following :

$array2 = ['android', 'iphone', 'windowsmobile'];

now the first array can be like either

$array1 = ['web', 'android', 'iphone'];

OR

$array1 = ['android']; // Not web

OR

$array1 = ['web', 'iphone']; // web+android

OR

$array1 = ['android', 'iphone'];

and never be web alone.

and $array2 will be same always.

Now I need to check is there any element in the first array is not there in the second array and to get this value. In the first and third case it is web and for the second case there is nothing.

How this can be done ?

This might help https://www.php.net/manual/en/function.array-diff.php — Aakash Martand, Apr 24 '19 at 06:51
@HappyCoder Do one thing, besides that every dynamic $array1, write output you are expecting so that we will work as per that. Because, we still don't know what you are trying to achieve — Rahul, Apr 24 '19 at 06:57
@HappyCoder You should really do what RahulMeshram says: Show us your expected output for every case. — yunzen, Apr 24 '19 at 07:03

yunzen · Accepted Answer · 2019-05-03T12:27:15.473

<?php


$array2 = ['android', 'iphone', 'windowsmobile'];

$array1 = ['web', 'android', 'iphone'];
print_r(array_diff($array1, $array2));

$array1 = ['android']; // Not web
print_r(array_diff($array1, $array2));

$array1 = ['web', 'iphone']; // web+android
print_r(array_diff($array1, $array2));

$array1 = ['android', 'iphone'];
print_r(array_diff($array1, $array2));

?>

Output

Array(
 [0] => web
)
Array(
)
Array(
 [0] => web
)
Array(
)

See it in action on 3v4l.org

Find element exists in first array and not in second for dynamic arrays

1 Answers1

Output