Extract Json values as Map with lift-json

Question

The documentation for lift-json suggests that I should be able to call 'values' to get my current JObject structure as a vanilla Scala Map. This approach is not working for me, as the return type of 'values' is json.Values rather than a Map as the examples show. What am I doing wrong? Is there an implicit import necessary to accomplish this conversion?

scala> val json = parse("""{"k1":"v1","k2":"v2"}""")         
json: net.liftweb.json.package.JValue = JObject(List(JField(k1,JString(v1)), JField(k2,JString(v2))))

scala> json.values                                  
res4: json.Values = Map((k1,v1), (k2,v2))

scala> res4.get("k1")                                        
<console>:18: error: value get is not a member of json.Values
   res4.get("k1")

possible duplicate of [Can I use the Scala lift-json library to parse a JSON into a Map?](http://stackoverflow.com/questions/3843000/can-i-use-the-scala-lift-json-library-to-parse-a-json-into-a-map) — Janx, Apr 06 '11 at 21:39

score 9 · Accepted Answer · edited May 23 '17 at 12:26

9

Somehow I missed the duplicate of this in my search: Can I use the Scala lift-json library to parse a JSON into a Map?

Answer is to cast explicitly:

json.asInstanceOf[JObject].values

edited May 23 '17 at 12:26

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answered Apr 06 '11 at 21:40

Janx

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Extract Json values as Map with lift-json

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