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I am trying to create a cicd pipeline with openshift. Initially, when creating the application using 'oc new-app' command, it automatically triggers the build. How i need to disable the initial build other than deleting or cancel the build?

Daein Park
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Pragathibaskar
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1 Answers1

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How i need to disable the initial build other than deleting or cancel the build?

oc new-app can not prevent the initial build.
It had discussed here: https://github.com/openshift/origin/issues/15429
Unfortunately it does not implement now.

But, you can prevent initial build as removing all triggers from buildConfig by modifying yaml of buildConfig manually.

  • First export oc new-app as yaml format.
# oc new-app --name=test \
  centos/ruby-25-centos7~https://github.com/sclorg/ruby-ex.git -o yaml --dry-run > test.yml
  • Remove all triggers as changing the configuration to triggers: [].
strategy:
  sourceStrategy:
    from:
      kind: ImageStreamTag
      name: ruby-25-centos7:latest
  type: Source
triggers: []

After modifying, create resources using oc create -f.

# oc create -f test.yml
imagestream.image.openshift.io/ruby-25-centos7 created
imagestream.image.openshift.io/ruby-ex created
buildconfig.build.openshift.io/ruby-ex created
deploymentconfig.apps.openshift.io/ruby-ex created
service/ruby-ex created

The build does not run until you run oc start-build <bc name> and oc rollout latest dc/<dc name>.

I hope this use case is helpful for you.

Daein Park
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  • Thank you for the solution. It is helpfull. Is there any other way to do this automatically through command other than editing the build configuration manually? – Pragathibaskar Apr 17 '19 at 06:23
  • @Pragathibaskar Unfortunately AFAIK, no, it isn't. There is no way unless modifying directly original template yaml. – Daein Park Apr 17 '19 at 06:37
  • I did like this, export COUNT=`oc get build|grep build-name|wc -l` ; oc apply -f ocp/buildconfig.yaml --wait=true; if [[ "$COUNT" != "0" ]]; then oc start-build build-name --wait=true fi – Ricky Vene Feb 28 '23 at 22:20