Creating RPM from current directory

Question

I'm trying to create an rpm from local source. Is it possible to do compilation in a similar to what pdebuild does - just copy the local directory as the source and operate on that copy? Every time I do rpmbuild -ba ... it tries to unpack some archive in RPMBUILD/SOURCE, but I don't want to go that way.

Essentially I'd like to be able to just checkout the repository with the code, do rpmbuild -ba application.spec in that checkout directory and have it do the right thing... Is that possible?

Even now after years passed, you'd probable need to use `--define` to define the rpmbuild paths. — Pavel Šimerda, Nov 02 '17 at 23:04

score 6 · Answer 1 · answered Nov 02 '17 at 23:05

6

I don't know about a better way than the following:

rpmbuild -bs my_file.spec --define "_sourcedir $PWD"

For my own project, I'm always using a Makefile to define make rpm once and then just use it.

answered Nov 02 '17 at 23:05

Pavel Šimerda

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score 0 · Answer 2 · answered Dec 22 '11 at 17:04

0

The %setup macro in the spec file is what unpacks the source. Remove that, and your problem goes away, and you can do anything you'd like to fetch the source.

answered Dec 22 '11 at 17:04

Corey Henderson

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Creating RPM from current directory

2 Answers2