How to do two select with joins from the cte's which returns total number of columns in the two selects?
I tried doing union but that appends to the same list and there is no way to differentiate for further use.
WITH campus AS
(SELECT DISTINCT CampusName, DistrictName
FROM dbo.file
),creditAcceptance AS
(SELECT CampusName, EligibilityStatusFinal, CollegeCreditAcceptedFinal, COUNT(id) AS N
FROM dbo.file
WHERE (EligibilityStatusFinal LIKE 'Eligible%') AND (CollegeCreditEarnedFinal = 'Yes') AND (CollegeCreditAcceptedFinal = 'Yes')
GROUP BY CampusName, EligibilityStatusFinal, CollegeCreditAcceptedFinal
),eligibility AS
(SELECT CampusName, EligibilityStatusFinal, COUNT(id) AS N, CollegeCreditAcceptedFinal
FROM dbo.file
WHERE (EligibilityStatusFinal LIKE 'Eligible%')
GROUP BY CampusName, EligibilityStatusFinal, CollegeCreditAcceptedFinal
)
SELECT a.CampusName, c.[EligibilityStatusFinal], SUM(c.N) AS creditacceptCount
FROM campus as a FULL OUTER JOIN creditAcceptance as c ON a.CampusName=c.CampusName
WHERE (a.DistrictName = 'xy')
group by a.CampusName ,c.EligibilityStatusFinal
Union ALL
SELECT a.CampusName , b.[EligibilityStatusFinal], SUM(b.N) AS eligible
From Campus as a FULL OUTER JOIN eligibility as b ON a.CampusName = b.CampusName
WHERE (a.DistrictName = 'xy')
group by a.CampusName,b.EligibilityStatusFinal
Expected output:
+------------+------------------------+--------------------+
| CampusName | EligibilityStatusFinal | creditacceptCount |
+------------+------------------------+--------------------+
| M | G | 1 |
| E | NULL | NULL |
| A | G | 4 |
| B | G | 8 |
+------------+------------------------+--------------------+
+------------+------------------------+----------+
| CampusName | EligibilityStatusFinal | eligible |
+------------+------------------------+----------+
| A | G | 8 |
| C | G | 9 |
| A | T | 9 |
+------------+------------------------+----------+