Why java.util.InputMismatchException?

Question

I'm trying to handle an exception but I receive something else. I dont know why I receive this.

Exception in thread "main" java.util.InputMismatchException
    at java.base/java.util.Scanner.throwFor(Scanner.java:939)
    at java.base/java.util.Scanner.next(Scanner.java:1594)
    at java.base/java.util.Scanner.nextInt(Scanner.java:2258)
    at java.base/java.util.Scanner.nextInt(Scanner.java:2212)
    at P4.main(P4.java:28)

I want to handle ArrayOutOfBoundsException. Thank you!

public class P4 {
    public static void main(String args[]) {
        Scanner keyboard=new Scanner(System.in);
        ArrayList <Double> sir = new ArrayList<Double>();
        System.out.println("Please insert doubles: ");
        do {
            double x=keyboard.nextDouble();
            sir.add(x);
        }while(keyboard.hasNextDouble());
        System.out.println("Elements in the array are: " + sir);
        System.out.println("Enter the index of the required element: ");
        try {
            int element = keyboard.nextInt();
            System.out.println("Element in the given index is :: "+sir.get(element));
        } catch(ArrayIndexOutOfBoundsException e) {
            System.out.println("The index you have entered is invalid");
        }
    }
}

Possible duplicate of [InputMismatchException Error](https://stackoverflow.com/questions/11270048/inputmismatchexception-error) — L Y E S - C H I O U K H, Apr 10 '19 at 15:16
"I want to handle ArrayOutOfBoundsException" you're not *getting* an ArrayOutOfBoundsException. — Andy Turner, Apr 10 '19 at 15:36
But you're not. You're failing when you try to read the index. — Andy Turner, Apr 10 '19 at 15:39
You are getting downvotes because you show an Java exception that shows an instance of an `InputMismatchExceptio`, while the answer you added shows you having a different problem — Ferrybig, Apr 10 '19 at 15:52
I was getting that error until I modified from ArrayIndexOutOfBoundsException to IndexOutOfBoundsException. I don't know why I was getting that error. — Sebi Cioată, Apr 11 '19 at 05:49

score -1 · Answer 1 · edited Apr 11 '19 at 21:32

-1

I modified from catch(ArrayIndexOutOfBoundsException e) to catch(IndexOutOfBoundsException e) . This is the answer.

edited Apr 11 '19 at 21:32

pppery

3,731
22
33
46

answered Apr 10 '19 at 15:40

Sebi Cioată

53
1
7

Why java.util.InputMismatchException?

1 Answers1