Typescript check for the 'any' type

Question

Is it possible to check for the exact any type using typescript conditionals?

type IsAny<T> = T extends any ? true : never

type A = IsAny<any> // true
type B = IsAny<number> // never
type C = IsAny<unknown> // never
type D = IsAny<never> // never

Answer 1

Yeah, you can test for any:

type IfAny<T, Y, N> = 0 extends (1 & T) ? Y : N; 
type IsAny<T> = IfAny<T, true, never>;
type A = IsAny<any> // true
type B = IsAny<number> // never
type C = IsAny<unknown> // never
type D = IsAny<never> // never

The explanation for this is in this answer. In short, any is intentionally unsound, and violates the normal rules of types. You can detect this violation because it lets you do something crazy like assign 0 to 1.

Answer 2

another way to detect IsAny:

type IsAny<T> = (
  unknown extends T
    ? [keyof T] extends [never] ? false : true
    : false
);