In Jupyter with an ipython kernel, is there a canonical way to execute cells in a non-blocking fashion?
Ideally I'd like to be able to run a cell
%%background
time.sleep(10)
print("hello")
such that I can start editing and running the next cells and in 10 seconds see "hello" appear in the output of the original cell.
I have tried two approaches, but haven't been happy with either.
(1) Create a thread by hand:
def foo():
time.sleep(10)
print("hello")
threading.Thread(target=foo).start()
The problem with this is that "hello" is printed in whatever cell is active in 10 seconds, not necessarily in the cell where the thread was started.
(2) Use a ipywidget.Output
widget.
def foo(out):
time.sleep(10)
out.append_stdout("hello")
out = ipywidgets.Output()
display(out)
threading.Thread(target=foo,args=(out,)).start()
This works, but there are problems when I want to update the output (think of monitoring something like memory consumption):
def foo(out):
while True:
time.sleep(1)
out.clear_output()
out.append_stdout(str(datetime.datetime.now()))
out = ipywidgets.Output()
display(out)
threading.Thread(target=foo,args=(out,)).start()
The output now constantly switches between 0 and 1 lines in size, which results in flickering of the entire notebook.
This should be solvable wait=True
in the call to clear_output
. Alas, for me it results in the output never showing anything.
I could have asked about that issue, which seems to be a bug, specifically, but I wondered whether there is maybe another solution that doesn't require me doing all of this by hand.