How to return after restarting python?

Question

Here is code:

def test():
    //restarting python
    os.execv(sys.executable, [sys.executable] + sys.argv)
print("Successfull")
return("Succesfull")

It's restarting python but not returning or printing value.

You never call `test()`. What exactly are you trying to do here? — Alexander, Apr 01 '19 at 05:58
I have a function called restart() inside the class and i need to restart the python and retiurn status code as 200 and print "successfull" msg. — nrs, Apr 01 '19 at 06:03
This looks like an [XY problem](https://meta.stackexchange.com/questions/66377/what-is-the-xy-problem) — zvone, Apr 01 '19 at 06:41

Shanteshwar Inde · Accepted Answer · 2019-04-12T05:43:03.947

1

I think your indentation is not correct so please have look at beloow code:

def test():
    try:
        print("Successfull")
        return("Succesfull")
    except Exception:
        #do something
    finally:
        os.execv(sys.executable, [sys.executable] + sys.argv)


test()

Note: The finally statement will be executed even if an exception was caught.

edited Apr 12 '19 at 05:43

answered Apr 01 '19 at 05:59

Shanteshwar Inde

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How can i return "succesull" before executing os.execv(sys.executable, [sys.executable] + sys.argv) – nrs Apr 01 '19 at 06:16
1

@rts Why would you even want to return "successful" *before* runing `execv`? – zvone Apr 01 '19 at 06:42

How to return after restarting python?

1 Answers1