Xcode 10.1 "return" statement doesn't stop function execution

Question

The return statement in Xcode 10.1 is not honoured by debugger,

For eg.,

    func doSomething() {

        print("Task A")
        return

        print("Task B")
    }

This prints

Task A
Task B //This is not expected to be printed as we have a `return` before this line

Can someone help me!

That should not happen. Try a clean and rebuild. Sometimes Xcode loses its mind and does not rebuild your source files after you make changes. — Duncan C, Mar 21 '19 at 13:12
@DuncanC: It *does* happen (see the linked-to Q&A). Swift executes the statement `return print("Task B")`, which prints the string and returns void. – Whether that should be considered a bug or not is a different story. Inserting a semicolon helps. — Martin R, Mar 21 '19 at 13:14
@MartinR, well it's definitely not a bug, just a natural quirk of non-mandatory-semicolon syntax. — user28434'mstep, Mar 21 '19 at 13:28

score 8 · Accepted Answer · answered Mar 21 '19 at 13:12

8

Because expression after return is treated as argument of return.
So your code understood by compiler as:

func doSomething() {
    print("Task A")
    return print("Task B")
}

To prevent it you can use semicolon to explicitly separate this expressions.
Like that:

func doSomething() {
    print("Task A")
    return;
    print("Task B")
}

answered Mar 21 '19 at 13:12

ManWithBear

3

... as explained in https://stackoverflow.com/q/48887696/1187415 :) – Martin R Mar 21 '19 at 13:16
@MartinR yeah, I failed to find this question :D – ManWithBear Mar 21 '19 at 13:42

1 Answers1