Python SocketServer error upon connection

Question

I am running a Python server using the socketserver module in Python 3.1. Every time I get a connection from the client (which succeeds client side), my server receives an error. Here is my code:

import socket
import socketserver
import string
import struct

class Server(socketserver.BaseRequestHandler):
    def __init__(self):
        self.address = self.client_address[0]
        print("%s connected." % str(self.address[1]))
    def handle(self):
        message = self.request.recv(1024).decode().strip()
        print("%s sent: '%s'" % (self.address,message))

if __name__ == "__main__":
    server = socketserver.TCPServer(("localhost",22085), Server)
    print("Socket created. . .")
    print("Awaiting connections. . .")
    server.serve_forever()

And here is my error:

----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 49669)
----------------------------------------
Traceback (most recent call last):
  File "C:\Python31\lib\socketserver.py", line 281, in _handle_request_noblock
    self.process_request(request, client_address)
  File "C:\Python31\lib\socketserver.py", line 307, in process_request
    self.finish_request(request, client_address)
  File "C:\Python31\lib\socketserver.py", line 320, in finish_request
    self.RequestHandlerClass(request, client_address, self)
TypeError: __init__() takes exactly 1 positional argument (4 given)

The odd thing I noticed about the error is that the port it gives on the second line is different than the port I'm using. I'm not really sure what the error is here...

Thanks for the help.

score 4 · Accepted Answer · answered Apr 02 '11 at 21:19

4

Try calling the __init__ method of the superclass:

class Server(socketserver.BaseRequestHandler):
    def __init__(self):
        self.address = self.client_address[0]
        print("%s connected." % str(self.address[1]))
        super(Server,self).__init__()                  # Init your base class

answered Apr 02 '11 at 21:19

Adam Matan

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Thanks @Adam ! I did't realize I was overwriting the __init__ method. I'll accept your comment as the best once stackoverflow allows me. However, I'm still receiving the error because it takes more than one argument... is there any way to call my code when the object is created without overwriting the existing constructor? – pajm Apr 02 '11 at 21:24
try removing `decode()`, leaving it as `self.data = self.request.recv(1024).strip()`. See here: http://docs.python.org/release/3.1.3/library/socketserver.html#module-socketserver – Adam Matan Apr 02 '11 at 22:00

score 1 · Answer 2 · answered Mar 26 '21 at 01:42

Almost a decade later, I had the same problem. (Python 3.9)

Thanks to the voted answer above as guidance, I was able to find out that the Customised RequestHandler is expected to take 3 arguments, so I had to override a 3-parameter __init__ as follows to resolve the errors.

class ServerRequestHandler(socketserver.BaseRequestHandler):
    def __init__(self, request, client_addr, server):
                # Custom initialisation code here....
                super().__init__(request, client_addr, server)

Python SocketServer error upon connection

2 Answers2