I believe the person asking about the last usable IP in the Class C subnet they provided. If you break down that subnet into binary you would get:
11111111.11111111.11111111.00000000
--------------------------> /24 as there are 24 1's
Effectively there are 65536 available subnets in a /24 and 256 hosts per subnet. This is a simple question due to it being a /24 meaning the last octect is the only octect you are going to be using. Like someone mentioned in the comments, every subnet is usable but the "first" usable subnet would be 192.168.0.0/24 which would give you the usable range between .1->.254 leaving .0 as the network identifier and .255 for the broadcast.