how to input only part of filename in the command line in python

Question

head = csv.reader(open("header.csv"))

I have something like this. here is it possible to provide part of the input in the command line like this.

head = csv.reader(open("sys.argv[1]".csv"))

So that I can launch the script as

python test.py header

Possible duplicate of [How do I access command line arguments in Python?](https://stackoverflow.com/questions/4033723/how-do-i-access-command-line-arguments-in-python) — vahdet, Mar 18 '19 at 14:26

score 1 · Answer 1 · answered Mar 18 '19 at 14:26

1

head = csv.reader(open('{}.csv'.format(sys.argv[1])))

or in python 3.6 or later

head = csv.reader(open(f'{sys.argv[1]}.csv'))

answered Mar 18 '19 at 14:26

FHTMitchell

score 1 · Answer 2 · answered Mar 18 '19 at 15:47

1

head = csv.reader(open(f'{sys.argv[1]}.csv'))

answered Mar 18 '19 at 15:47

Uli Sotschok

2 Answers2