regex in python : shortest non overlapping matches

Asked Mar 18 '19 at 10:27

Active Mar 18 '19 at 10:36

Viewed 45 times

I'm trying to parse a string such as "ABCeRIsqABCSDABCsde" in order to extract "ABCeRIisq", "ABCSD" and "ABCsde".

I've managed to get the first occurrences with a lookahead assertion :

re.findall("ABC.*?(?=ABC)","ABCeRIsqABCSDABCsde")

['ABCeRIisq', 'ABCSD']

How can I get all the occurrences? Is there any way do this without lookahead ?

Thanks!

edited Mar 18 '19 at 10:36

asked Mar 18 '19 at 10:27

jmague

1

Use `r'ABC\S*?(?=ABC|$)'` – anubhava Mar 18 '19 at 10:29
Sure, that works, thanks. It still uses lookahead... – jmague Mar 18 '19 at 10:35
It is the alternation operator that matters here, and the end of string `$` anchor. – Wiktor Stribiżew Mar 18 '19 at 10:36

0 Answers0