How do I use pathlib to create files named for range of dates?

Question

I can print a range of filenames with the below code but I need to write empty files instead of printing. I know that pathlib.Path.touch and accomplish this but . . . do I need to define a method for the touch?

import datetime
import pathlib

for i in range(0, 180):
    print((datetime.date.today() + datetime.timedelta(i)).strftime("%Y%m%d" + ".exml"))

score 4 · Accepted Answer · answered Mar 13 '19 at 21:44

4

I don't think you need to define a method. Try this:

import datetime
import pathlib

for i in range(0, 180):
    fname = (datetime.date.today() + datetime.timedelta(i)).strftime("%Y%m%d" + ".exml")
    print((fname))
    pathlib.Path(fname).touch()

answered Mar 13 '19 at 21:44

REXXman

376
2
4

You nailed it! Thanks a million. – mr.zog Mar 13 '19 at 22:08
Why does it need to be print((fname))? What does the extra set of parens do? – mr.zog Mar 13 '19 at 22:09
1

The extra pair of parens are just that, extra. I didn't delete them when I moved the equation out of the print statement. Good catch. – REXXman Mar 14 '19 at 10:32

How do I use pathlib to create files named for range of dates?

1 Answers1