Stringtokenizer undefined

Question

Hi i got some problem making a stringtokenizer method which allow string input by user and count and print tokens. Can someone help me solve error? It says the constructor is undefined.

public class StringTokenizer
{
  public static void main(String[ ] args)
  {
      Scanner keyboard;
      String inputSentence;
      StringTokenizer stok = null; //declare a reference to hold the address of a StringTokenizer object
      keyboard = new Scanner(System.in);

      System.out.println("Enter a line of text: ");
      inputSentence = new String(keyboard.nextLine( ) );
      while(!(inputSentence.equals("quit")))
      {
          stok = new StringTokenizer(inputSentence);//the constructor that take a String and uses a space as the delimeter
          while (stok.hasMoreTokens());
          {
          System.out.println("Number of tokens: " + stok.countTokens( ));
          System.out.println(stok.nextToken( ));
          }




        System.out.println("Enter another line of data or quit\n" );
        inputSentence = keyboard.nextLine( );

    }
    System.out.println("Goodbye");



    }//end of main
} //end of class

Oh yes thanks for telling me the other error i forgot to list it as well. And yes the compiler says the errors was the constructor one in first place, I don't what constructor suppose to be with this as I remembered my professor said I only have to declare instance since the class is already in java.util package. I made another one with different class name to make it less confused and also imported java.util, the errors still happen. Can you help me with the constructor thing? — Dave Phan, Mar 13 '19 at 00:11

score 3 · Answer 1 · answered Mar 12 '19 at 23:53

3

Rename your class. You are shadowing java.util.StringTokenizer; alternatively,

java.util.StringTokenizer stok = null;

and

stok = new java.util.StringTokenizer(inputSentence);

But, it'll be less confusing if you rename your class.

answered Mar 12 '19 at 23:53

Elliott Frisch

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Agreed. It’s never a good idea to name your class the same as any class anywhere under the `java` package. – Bohemian Mar 13 '19 at 00:02
I made another class with different name, and also import java.util.*; the error still happens do you know why? – Dave Phan Mar 13 '19 at 00:02
@DavePhan You didn't remove the existing class in the current package with the name `StringTokenizer` (and thus you are still **shadowing** it). – Elliott Frisch Mar 13 '19 at 00:07
@ElliottFrisch I actually made the 2nd one on a different laptop and i also change the class name on the first one as well. The prior error said to be for the constructor but I have no idea what it is – Dave Phan Mar 13 '19 at 00:17
*The prior error said to be for the constructor* What is the new error? – Elliott Frisch Mar 13 '19 at 00:26
there's also errors on hasMoreTokens and nextToken as well, it's not new tho. I thought it's linked up to the constructor error so I forgot to mention in the post but @Carcigenicate reminded me that. – Dave Phan Mar 13 '19 at 00:42

Stringtokenizer undefined

1 Answers1