BASIC random function giving a syntax error, not sure what the problem is

Question

It's saying the error is just after the 11 but I can't figure it out please help

11 * RND(1) + 1;a

if a = 1 then let pinsb = 01110111  
if a = 2 then let pinsb = 00010100  
if a = 3 then let pinsb = 10110011  
if a = 4 then let pinsb = 10110110
if a = 5 then let pinsb = 11010100  
if a = 6 then let pinsb = 11100110
if a= 7 then let pinsb = 11100111   
if a = 8 then let pinsb = 00110100  
if a = 9 then let pinsb = 11110111  
if a = 10 then let pinsb = 11110100

Also declare &B for binary values, for example, pinsb=&B01110111 — eoredson, Mar 08 '19 at 04:49

score 1 · Answer 1 · answered Mar 12 '19 at 13:40

I'm assuming that this question is about the PICAXE microcontroller and its BASIC language, because of the [picaxe] tag. There are several things in the posted code that won't work in PICAXE BASIC so I guess you're familiar with a different dialect or are trying to take some code written for a different dialect and use it on a PICAXE. If this isn't the case, please let us know.

To get this code to work on a PICAXE you need to fix a few things:

You can't just assign to a new variable name; you need to use the built-in names b0, b1, b2 etc (byte variables) or w0, w1, w2 etc (word variables) unless you define another name for it using the symbol keyword.
To generate a random number, use the random keyword which assigns a random value to the word variable you specify.
You can only use the one-line if … then command with goto, gosub or exit. Otherwise you need to use an if … then … endif structure, but you can write this on a single line using : to separate the commands.
Finally, to specify a binary value you prefix it with a % character.

So I think what you're trying to do is this:

symbol a = w0             ; use the name 'a' for word variable w0
random a                  ; assign a random value of 0...65535 to a
a = a // 10 + 1           ; // is modulo i.e. remainder of a / 10, so result is in range 1 - 10

if a = 1 then : pinsB = %01110111 : endif 
if a = 2 then : pinsB = %00010100 : endif
if a = 3 then : pinsB = %10110011 : endif
if a = 4 then : pinsB = %10110110 : endif
if a = 5 then : pinsB = %11010100 : endif 
if a = 6 then : pinsB = %11100110 : endif
if a = 7 then : pinsB = %11100111 : endif
if a = 8 then : pinsB = %00110100 : endif
if a = 9 then : pinsB = %11110111 : endif
if a = 10 then : pinsB = %11110100 : endif

Always remember that each word variable is made up of two byte variables, so if you've used w0 you can't also use b0 or b1 at the same time, and so on.

eoredson · Answer 2 · 2019-03-08T05:26:29.030

0

Assign binary values based on a random value:

This program was written in QB64 which supports &B prefix whereas QB45 does not.

REM assign binary values based on a random value
a = INT(RND * 10 + 1)

IF a = 1 THEN LET pinsb = &B1110111
IF a = 2 THEN LET pinsb = &B10100
IF a = 3 THEN LET pinsb = &B10110011
IF a = 4 THEN LET pinsb = &B10110110
IF a = 5 THEN LET pinsb = &B11010100
IF a = 6 THEN LET pinsb = &B11100110
IF a = 7 THEN LET pinsb = &B11100111
IF a = 8 THEN LET pinsb = &B110100
IF a = 9 THEN LET pinsb = &B11110111
IF a = 10 THEN LET pinsb = &B11110100

edited Mar 08 '19 at 05:26

answered Mar 08 '19 at 04:57

eoredson

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Although the LET keyword is not longer used or necessary. – eoredson Mar 08 '19 at 05:01
I'm confused. The question is tagged [picaxe], not [quickbasic] or [qb64]. None of your answers will work in PICAXE BASIC. Am I missing something? – nekomatic Mar 11 '19 at 10:57
Sorry, I didn't see the PICAXE tag and assumed you were using QB. – eoredson Mar 11 '19 at 21:10

score 0 · Answer 3 · answered Mar 08 '19 at 05:42

Assign binary values based on a random value using a binary convert function:

REM assign binary values based on a random value using a binary convert function
A = INT(RND * 10 + 1)
IF A = 1 THEN pinsb = GetBinary("1110111")
IF A = 2 THEN pinsb = GetBinary("10100")
IF A = 3 THEN pinsb = GetBinary("10110011")
IF A = 4 THEN pinsb = GetBinary("10110110")
IF A = 5 THEN pinsb = GetBinary("11010100")
IF A = 6 THEN pinsb = GetBinary("11100110")
IF A = 7 THEN pinsb = GetBinary("11100111")
IF A = 8 THEN pinsb = GetBinary("110100")
IF A = 9 THEN pinsb = GetBinary("11110111")
IF A = 10 THEN pinsb = GetBinary("11110100")
END
FUNCTION GetBinary (B$)
    FOR V = LEN(B$) TO 1 STEP -1
        IF MID$(B$, V, 1) = "1" THEN
            X# = X# + 2 ^ (V - 1)
        END IF
    NEXT
    GetBinary = X#
END FUNCTION

Use this if you are not running QB64. – eoredson Mar 08 '19 at 06:03 — eoredson, Mar 08 '19 at 06:03

score 0 · Answer 4 · answered Mar 08 '19 at 06:35

Assign binary values based on a random value using a binary convert function reading values from data.

REM assign binary values based on a random value using a binary
REM convert function reading values from data.
RANDOMIZE TIMER ' reseed rnd
A = INT(RND * 10 + 1)
RESTORE
FOR X = 1 TO A
    READ X$
NEXT
pinsb = GetBinary(X$)
PRINT "pinsb="; pinsb
END
DATA "1110111","10100","10110011","10110110","11010100"
DATA "11100110","11100111","110100","11110111","11110100"
FUNCTION GetBinary (B$)
    FOR V = LEN(B$) TO 1 STEP -1
        IF MID$(B$, V, 1) = "1" THEN
            X# = X# + 2 ^ (V - 1)
        END IF
    NEXT
    GetBinary = X#
END FUNCTION

BASIC random function giving a syntax error, not sure what the problem is

4 Answers4