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Suppose I have a class 

Class Apple<T> where T: IComparable<int>{}

Now while creating an object for Apple I'll do it like

Apple<int> obj = new Apple<int>();

The above code will work.

If I replace the same code with any other Generic Interface like IComparer<>,IEnumerable<> etc.. object creation like the above will not work and we have to declare it like

Apple<IEnumerable<int>> obj = new Apple<IEnumerable<int>>();

Why is it like that? Why is it the way which i declared for IComparable<> is only working for it and not for any other interface?

Pintu Paul
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srikar kulkarni
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1 Answers1

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Nothing special about IComparable<T>, but about T itself, which - in case of int- also implements IComparable<int>. However int surely does not implement IEnumerable<int>.

Or in other words: you can of course compare every int with another int. However you can´t iterate an int.

Bakudan
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MakePeaceGreatAgain
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