How to pass function as pytest parameterize fixture?

Question

How can I pass a function as a parameter in Python? I want to do something like the code below.

My goal is to pass different parameters to test a single function.

def __internal_function(inputs):
    a,b,c,d = inputs

    new_value_of_b = copy.deepcopy(b)

    name = b['name']
    age = b['age']
    weight = b['weight']
    height = b['height']

    new_value_of_b2 = [name, age, weight, height]
    new_value_of_b3= new_value_of_b['weight']['unit'] = 'cm'
    del new_value_of_b['age']
    return new_value_of_b,new_value_of_b2,new_value_of_b3


@pytest.mark.parametrize('values',__internal_function,'expected_code',[100,200,300])
assert func(__internal_function)== expected_code

yes its variable.i want to achieve: func(new_value_of_b)==100, func(new_value_of_b2)==200 and func(new_value_of_b3) == 300 — darshpreet narula, Mar 01 '19 at 10:18
You seem to be missing your test function. I see the `@pytest.mark ...` and an `assert`, but don't you need a function definition between the two? — quamrana, Mar 01 '19 at 10:23
Please provide code which can be run and the traceback is inspected. There is no test function in the code sample. — SilentGuy, Mar 01 '19 at 20:21

score 0 · Answer 1 · answered Mar 01 '19 at 20:20

0

If you are using two variables as parameters, the correct syntax is:

@pytest.mark.parametrize(('values','expected_code'),(_internal_function,[100,200,300]))

You can use function as a parameter if its output is an iterable.

answered Mar 01 '19 at 20:20

SilentGuy

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How to pass function as pytest parameterize fixture?

1 Answers1