struct.pack() returns a blank value

Question

When I try to do the following:

struct.pack("B",32)

The 32 is a int type.

I am expecting "\x20", but I get the following (blank): " "

I need this as a byte using struct() because I want to put it in a bytearray(), to look like this:

bytearray(b'\x20')

I've tried other encoding on the struct.pack() besides "B", but I could've left something out.

If you print the content of a bytearray, all bytes whose values correspond to an ASCII character are represented by that character, for convenience. — Thierry Lathuille, Feb 22 '19 at 10:00

score 0 · Answer 1 · answered Feb 22 '19 at 09:59

0

space char is 0x20 on the ascii table

>>> print(b'\x20')
b' '
>>> struct.pack('B', 32)
b' '

answered Feb 22 '19 at 09:59

ShmulikA

score 0 · Accepted Answer · answered Feb 22 '19 at 10:21

0

If you do this:

>>> b" " == bytearray(b"\x20")
True

you will see that you are getting what you are expecting, just in a representation that you are not expecting.

answered Feb 22 '19 at 10:21

BoarGules

Yes, I what you mean now. I was concerned that this was being converted to some other type of value which wasn't what I wanted. Other people's answers/comments also say the same, but I'll mark your answer as it is the clearest in explaining this so far. Many thanks! – NMSilva Feb 22 '19 at 10:52

2 Answers2