You can do it with help of indexOf
function.
SELECT *
FROM test_sof
┌─f1─┬─f2──────┬─f3────────────┐
│ a │ [1,2,3] │ ['x','y','z'] │
└────┴─────────┴───────────────┘
┌─f1─┬─f2────────┬─f3────────────────┐
│ c │ [7,8,9,0] │ ['x','y','z','n'] │
└────┴───────────┴───────────────────┘
┌─f1─┬─f2─────────┬─f3────────────────┐
│ d │ [7,8,9,11] │ ['x','y','z','n'] │
└────┴────────────┴───────────────────┘
┌─f1─┬─f2──────┬─f3────────────┐
│ b │ [4,5,6] │ ['x','y','z'] │
└────┴─────────┴───────────────┘
4 rows in set. Elapsed: 0.001 sec.
Then:
SELECT
f1,
f2[indexOf(f3, 'x')] AS x,
f2[indexOf(f3, 'y')] AS y,
f2[indexOf(f3, 'z')] AS z,
f2[indexOf(f3, 'n')] AS n
FROM test_sof
ORDER BY
f1 ASC,
x ASC
┌─f1─┬─x─┬─y─┬─z─┬──n─┐
│ a │ 1 │ 2 │ 3 │ 0 │
│ b │ 4 │ 5 │ 6 │ 0 │
│ c │ 7 │ 8 │ 9 │ 0 │
│ d │ 7 │ 8 │ 9 │ 11 │
└────┴───┴───┴───┴────┘
4 rows in set. Elapsed: 0.002 sec.
Keep in mind situation when index from header array will not be present in data array or vise-versa.
UPD: the way how to get data without knowing "headers".
You will get three columns, third one with headers.
SELECT
f1,
f2[num] AS f2_el,
f3[num] AS f3_el
FROM test_sof
ARRAY JOIN arrayEnumerate(f2) AS num
ORDER BY f1 ASC
┌─f1─┬─f2_el─┬─f3_el─┐
│ a │ 1 │ x │
│ a │ 2 │ y │
│ a │ 3 │ z │
│ b │ 4 │ x │
│ b │ 5 │ y │
│ b │ 6 │ z │
│ c │ 7 │ x │
│ c │ 8 │ y │
│ c │ 9 │ z │
│ c │ 0 │ n │
│ d │ 7 │ x │
│ d │ 8 │ y │
│ d │ 9 │ z │
│ d │ 11 │ n │
└────┴───────┴───────┘
14 rows in set. Elapsed: 0.006 sec.