Override list(object)

Question

How do you override list(object) where object is an object defined by a class. Can you do something like

class foo:
    def __list__(self):
        return [None] # In my real code I want it to return a object

It would also be helpful if someone found a question with the answer I'm looking for.

"In my real code I want it to return a object" So return that object? It is unclear what exactly you are trying to achieve and what is stopping you from achieving that — DeepSpace, Feb 16 '19 at 22:32

score 1 · Accepted Answer · answered Feb 16 '19 at 22:39

1

You can define __iter__ method to make your object iterable. list can then create results based on the resulting iterator. You can also use yield generator syntax:

class Foo:
    def __iter__(self):
        yield None

print(list(Foo())) # prints [None]

answered Feb 16 '19 at 22:39

zch

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Thanks! This worked. Also does list depend on___len____? – Raymond Feb 23 '19 at 22:21
@RaymondPeng, no, it will accumulate all results of a generator, regardless of length. – zch Feb 24 '19 at 00:28
By the way, this answer is actually pretty similar to https://stackoverflow.com/a/46627087/10818862 – Raymond Feb 25 '19 at 02:38

Override list(object)

1 Answers1