How to click button in dialog box using PyWinAuto

Question

I have an batch file that I execute that opens a program. A dialog box then appears which I type into it the username and password credentials

The I print the control identifiers and it lists;

SunAwtDialog - 'Login'    (L528, T242, R853, B501)
['SunAwtDialog', 'LoginSunAwtDialog', 'Login']
child_window(title="Login", class_name="SunAwtDialog")

So after reading this post. My understanding was to use window + the button and a click method like so;

dlp.SunAwtDialog['Login'].click()

But this keeps throwing an ElementNotFoundError;

ElementNotFoundError: {'best_match': 'SunAwtDialog', 'top_level_only': False, 'parent': <win32_element_info.HwndElementInfo - 'Login', SunAwtDialog, 2164976>, 'backend': 'win32'}

Below is the full snippet of code;

from pywinauto import application
import time
app = application.Application()
app.start(r"C:\\WINDOWS\system32\cmd.exe", wait_for_idle=False)
dlg = app.top_window()
dlg.type_keys('D:{ENTER}')
dlg.type_keys('cd{SPACE}Software\\client{ENTER}')
dlg.type_keys('run_client.bat{ENTER}')
time.sleep(10)
new_app = application.Application().connect(title="iManager")
dlp = new_app.top_window()
#type username + password
dlp.type_keys('user')
dlp.type_keys('{TAB}')
dlp.type_keys('pass')
#print control identifiers
dlp.print_control_identifiers()
#click login[![enter image description here][1]][1]
dlp.SunAwtDialog['Login'].click()

You can see on the image below the "Login" button I want to be able to click. There is also another button next to the "Server" option, but it is not in my control identifiers

You can see in the error that `'backend': 'win32'`. You may try to use `Application(backend="uia")` and `Inspect.exe` as a spy tool. This is all described in the [Getting Started Guide](https://pywinauto.readthedocs.io/en/latest/getting_started.html). — Vasily Ryabov, Feb 13 '19 at 14:44
This issue with that was that when I attempted it with `backend="uia"` it threw an error saying `ElementNotEnabled` — mp252, Feb 13 '19 at 14:53
Sorry @VasilyRyabov ignore me, got the correct control identifiers up now. Also another question, if it needs to be moved to a separate one please let me know. But does this package work well with a java built application? As I had problems with the last tool I was using and that was specific to RPA — mp252, Feb 13 '19 at 14:57
It depends which Java framework was used to build the GUI. As I remember JavaFX supports MS UI Automation API pretty well (yes, it's OS level API, pywinauto just wraps it around with some syntax sugar). Not sure about Swing/AWT apps as they are pretty old. — Vasily Ryabov, Feb 13 '19 at 21:51
`Inspect.exe` uses MS UI Automation API as well (you need to switch to "UI Automation" mode). This is almost the only indicator of GUI testability now. — Vasily Ryabov, Feb 13 '19 at 21:53
Thank you, I will try it `Inspect.exe` out as at the moment, the only button I can get to click is the `Cancel` button. — mp252, Feb 14 '19 at 09:03

score 1 · Answer 1 · answered Sep 17 '19 at 23:53

1

A solution that I use for this is using send_keys. Try this:

from pywinauto.keyboard import send_keys
send_keys("{VK_MENU down}" "l" "{VK_MENU up}")

answered Sep 17 '19 at 23:53

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347
1
15

score 0 · Answer 2 · edited Mar 14 '23 at 15:13

The good solution for this is pressing the "Enter" if there is only an "OK" button on that Dialog/Message/Alert/Information box. For this you can use:

send_keys("{ENTER}")

If that doesn't work correctly, you can use the sleep command to wait for 1-2 seconds and then press enter, like so:

time.sleep(2)
send_keys("{Enter}")

For this, you have to import two libraries:

from pywinauto.keyboard import send_keys
import time

How to click button in dialog box using PyWinAuto

2 Answers2