multiple default optional values

Question

I have a function that accepts two integers with default value, is there a way to allow the caller of the functions to pass as many parameters as he wants? (first but not second, second but not first, both). example:

void do_something(int first = 0, int second = 0);

int main()
{
   do_something(1); // first - how to declare it's the first argument
   do_something(1); // second
   do_something(1,1); 
   do_something();
   return 0; // I want to allow all those options
}

`do_something(1); // second` - this is not possible. You have to pass default parameter explicitly: `do_something(0, 1);`. The rest of them is fine. — Yksisarvinen, Feb 10 '19 at 11:53

score 0 · Answer 1 · edited Feb 10 '19 at 13:15

0

Use another wrapper inline function

   void DoSomething(int f = 0 , int s = 0)
   {}
   void inline DoSomethingS(int s = 0)
   {DoSomething(0 , s);}

If the user wants to send the second and leave the first optional he'll use the DoSomething+options in this case DoSomethingS.

edited Feb 10 '19 at 13:15

Paul Sanders

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answered Feb 10 '19 at 12:03

tomer zeitune

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Declare first and then implement without default arguments :) – tomer zeitune Feb 10 '19 at 13:16
I missed the trailing S, sorry. – Paul Sanders Feb 10 '19 at 13:16
@PaulSanders np so you got it working ? – tomer zeitune Feb 10 '19 at 14:41
Your solution looks fine, yes. – Paul Sanders Feb 10 '19 at 17:43
So mark the V next to my answer – tomer zeitune Feb 10 '19 at 21:16
I am not the OP – Paul Sanders Feb 10 '19 at 23:11
@PaulSanders oh sorry – tomer zeitune Feb 11 '19 at 05:32

multiple default optional values

1 Answers1