Arrange words in array in php

Question

Rearrange words in Array based on position of the first array. In my code there are two array my first array is the base array from which i am going to compare it with second array and make the position same as first array.

Consider 2 input By considering 1 input as base i am applying levenshtein(metaphone(each word database),metaphone(each word of bank)) then based on that arranging the words of bankdata in new array

databaseName = LAL BAHADUR SHASTRI bankdata = SHASTRI LAL source code will only rearrange bankdata and stored in in new array current output of bankdata : LAL SHASTRI

Rearrangement is happening properly just need to arrange words in array

            $db = 'LAL BAHADUR SHASTRI YADAV';
            $bank = 'SHASTRI LAL';
            $a = reArrangeArray($db,$bank);

            function reArrangeArray($db,$bank)
            {
                $dataBaseName = $db;
                $bankdataRows = [$db,$bank,];
                $dbWords = preg_split("#[\s]+#", $dataBaseName);     
                foreach ($bankdataRows as $bankdata)
                {
                $bankWords = preg_split("#[\s]+#", trim($bankdata));
                $result    = [];    
                if(!empty($bankWords))
                    foreach ($dbWords as $dbWord)
                    {
                    $idx   = null;
                    $least = PHP_INT_MAX;
                    foreach ($bankWords as $k => $bankWord)
                        if (($lv = levenshtein(metaphone($bankWord),metaphone($dbWord))) < $least)
                        {
                        $least = $lv;
                        $idx   = $k;
                        }
                    @$result[] = $bankWords[$idx];
                    unset($bankWords[$idx]);
                    }
                $result = array_merge($result, $bankWords);
                var_dump($result);
                }
            }

Case 1: CURRENT OUTPUT

            array (size=4)
            0 => string 'LAL' (length=3)
            1 => string 'BAHADUR' (length=7)
            2 => string 'SHASTRI' (length=7)
            3 => string 'YADAV' (length=5)

            array (size=4)
            0 => string 'LAL' (length=3)
            1 => string 'SHASTRI' (length=7)
            2 => null
            3 => null

Expected Output

I need array position as same as databaseArray

            $dbName = 'LAL BAHADUR SHASTRI YADAV';
            $bankName = 'SHASTRI LAL';

            array of db (size=4)
            0 => string 'LAL' (length=3)
            1 => string 'BAHADUR' (length=7)
            2 => string 'SHASTRI' (length=7)
            3 => string 'YADAV' (length=5)

            array of bankname (size=4)
            0 => string 'LAL' (length=3)
            1 => #
            2 => string 'SHASTRI' (length=7)
            3 => ###

if word not found in first array it should be place with # since position is 3 which dont have matching element it has 3 #

Case 2

Input :

$dbName = NikithaRani MohanRao $bankdata = Nikitha Rani Mohan Rao

Output : $newbankdata = NikithaRani MohanRao

It should concatenate the word if found concatenated in $dbName

What's Levenish distance? A Google search [finds no matches](https://www.google.com/search?q="leventish+distance"). Do you perhaps mean *Levenshtein* distance? — Mark Amery, Jan 31 '19 at 18:07

score 0 · Accepted Answer · answered Aug 12 '19 at 14:47

            <?php  
            $DatabaseName = "LAL BAHADUR SHASTRI YADAV";
            $BankName = "SHASTRI LAL";

            $data = explode(" ", $DatabaseName);
            $bank = explode(" ", $BankName);
            sort($data);
            sort($bank);
            if($data == $bank){
                echo "true";
                exit;
             }

            $lev = 0;
            foreach($data as $key => $name){
                $lev += levenshtein($name, $bank[$key]);
            } 
            echo PHP_EOL . $lev; 
            ?>

Arrange words in array in php

1 Answers1