List with range of values of given length

Question

I want to give paramters valueFrom, valueTo and length.out. The same how seq function works in R:

seq(0, 1, length.out = 5)

0.00 0.25 0.50 0.75 1.00

How to do it in python?

Is the only solution is:

range(valueFrom, valueTo, by=(valueTo - ValueFrom)/(lengthOut - valueTo - ValueFrom)) ?

Python is really messy language in compare with R or Java.

"Python is really messy language in compare with R or Java" - I think otherwise my good sir — Jab, Jan 31 '19 at 08:56
Although the only error in my comment is I am assuming OP's gender. *(hope I'm right)* — Jab, Jan 31 '19 at 08:58
In python even I can't use letters like `ć` in comments !!! ERROR `SyntaxError: Non-UTF-8 code starting with '\xe6'`. Python is really awkward. — stakowerflol, Jan 31 '19 at 09:05
@stakowerflol it's usually frowned upon to comment code in any other language than English — ruohola, Jan 31 '19 at 09:15
@stakowerflol you absolutely can. What editor are you using? What encoding is the source file saved in? See the first two paragraphs in [this answer](https://stackoverflow.com/a/23092402/4570170). — Chillie, Jan 31 '19 at 09:18

yatu · Answer 1 · 2019-01-31T09:03:41.940

2

In python you can use np.arange for this:

import numpy as np
np.arange(0,1.25,0.25)
array([0.  , 0.25, 0.5 , 0.75, 1.  ])

Or if you want to create a sequence by specifying its length use np.linspace:

np.linspace(0,1,5)
array([0.  , 0.25, 0.5 , 0.75, 1.  ])

edited Jan 31 '19 at 09:03

answered Jan 31 '19 at 08:55

yatu

Note that the OP wants to specify the length of the sequence, not the step – awesoon Jan 31 '19 at 08:57

score 2 · Accepted Answer · edited Jan 31 '19 at 09:00

2

Use NumPy module, it has many useful functions

import numpy as np
print(np.linspace(0, 1, 5))

edited Jan 31 '19 at 09:00

taurus05

answered Jan 31 '19 at 08:59

Mikhail Efimov

2 Answers2