swift cant create a child in firebase database

Question

I am trying to create a child in an empty firebase database using Swift, the code is running without any errors but I don't see the changes in the database. the code:

let ref = Database.database().reference()
ref.child("Branches")

I change the code to: let ref = Database.database().reference().child("Branches") let values = ["Email" : SEmailTextField.text] ref.updateChildValues(values as [AnyHashable : Any]) { (err, reference) in print(err ?? "non") } but it's doesn't work — Mor Goren, Jan 31 '19 at 12:27
is the text attribute not empty? Have you configured Firebase on your project? What error does it prints? — Gustavo Vollbrecht, Jan 31 '19 at 13:16
Error Domain=com.firebase Code=1 "Permission denied" UserInfo={NSLocalizedDescription=Permission denied} https://coface-2148b.firebaseio.com/Branches this is the error — Mor Goren, Jan 31 '19 at 13:42
If you're having trouble with that, it should be approached as another question, otherwise this one will get messy. — Gustavo Vollbrecht, Jan 31 '19 at 13:59
Check security rules: https://firebase.google.com/docs/database/security/ — Gustavo Vollbrecht, Jan 31 '19 at 14:02
my firebase rules: { "rules": { ".read": true, ".write": true } } — Mor Goren, Jan 31 '19 at 14:10
You shouldn't be getting that error if your rules are like that, make sure you configured everything. https://firebase.google.com/docs/database/ios/start — Gustavo Vollbrecht, Jan 31 '19 at 14:20
Also, check this: https://stackoverflow.com/questions/47984114/firebase-permission-denied — Gustavo Vollbrecht, Jan 31 '19 at 14:36
yes, thank you! I did all the setups from the beginning and it worked — Mor Goren, Feb 07 '19 at 09:47

Gustavo Vollbrecht · Accepted Answer · 2019-02-14T13:13:49.087

6

You're not adding values to the database.

In Firebase, you create additional childs as soon as you set new values.

You can use setValue or updateChildValues to add values.

Example:

let ref = Database.database().reference().child("branches")

let values = ["any_key" : "any_value"]
ref.updateChildValues(values) { (err, reference) in
    // handle errors or anything related to completion block.
}

Docs: https://firebase.google.com/docs/database/ios/read-and-write

Note: Make sure you configured everything correctly: https://firebase.google.com/docs/database/ios/start

edited Feb 14 '19 at 13:13

answered Jan 30 '19 at 18:30

Gustavo Vollbrecht

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Is it not possible to create a child without input? I can create one online on Firebase but not with coding? – submariner May 15 '22 at 14:46

score 1 · Answer 2 · answered Jan 30 '19 at 18:38

It's depend on your database structure let suppose you create

{ 
      "users": {
        "uid": userID,
            "username": "string"
      }
}

this time data then you can get it as you mention in your question

var ref: DatabaseReference!
ref = Database.database().reference()
self.ref.child("users").child(user.uid).setValue(["username": username])

In this can be some mistake but you have to understand concept,

swift cant create a child in firebase database

2 Answers2