Java - Set Period

Question

I want to make an analysis of some time barriers and I'm having some doubts about the best approach to define 'Period'.

I'm working with time passed from the start, I mean:

Start - "00:00:00"
Checkpoint 1 - "2:10:02"
End - "03:00:00"

So, what kind of object should I use to translate the string? Later I'll want to make some averages, etc.

[Period::between](https://docs.oracle.com/javase/8/docs/api/java/time/Period.html#between-java.time.LocalDate-java.time.LocalDate-) — achAmháin, Jan 21 '19 at 14:44
Perhaps you're looking for [`Duration.parse()`](https://docs.oracle.com/javase/10/docs/api/java/time/Duration.html#parse(java.lang.CharSequence)) (requires Java 8 or later). — John Bollinger, Jan 21 '19 at 14:48
[`Duration`](https://docs.oracle.com/javase/9/docs/api/java/time/Duration.html). It prints differently, but search for questions about parsing and formatting the format with colons that you use, they are out there. — Ole V.V., Jan 22 '19 at 10:15
I take it that the times are relative to the start time? Not times of day, are they? — Ole V.V., Jan 22 '19 at 10:16

score 0 · Answer 1 · answered Jan 21 '19 at 15:00

0

If you can use LocalTime for example, you could use this and manipulate it however necessary:

String start = "02:10:02";
String end = "03:00:00";

LocalTime lt = LocalTime.parse(start);
LocalTime lt2 = LocalTime.parse(end);
Duration dur = Duration.between(lt, lt2);
System.out.println("Diff is: " + dur.getSeconds());

Output:

Diff is: 2998

Then do whatever you need with the seconds.

answered Jan 21 '19 at 15:00

achAmháin

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If the times are not time of day, `LocalTime` is incorrect. `Duration` is good under all circumstances. – Ole V.V. Jan 22 '19 at 10:18

score 0 · Answer 2 · answered Jan 21 '19 at 15:00

You could use LocalTime and Duration although you will need a custom format to parse time with single hour digit.

DateTimeFormatter fmt = DateTimeFormatter.ofPattern("H:mm:ss");

LocalTime start = LocalTime.parse("00:00:00", fmt);
LocalTime checkpoint = LocalTime.parse("2:10:02", fmt);
LocalTime end = LocalTime.parse("03:00:00", fmt);

System.out.println(Duration.between(start, checkpoint)); // PT2H10M2S
System.out.println(Duration.between(checkpoint, end)); // PT49M58S
System.out.println(Duration.between(start, end)); // PT3H

If the times are not time of day, `LocalTime` is incorrect. – Ole V.V. Jan 22 '19 at 10:18 — Ole V.V., Jan 22 '19 at 10:18

Java - Set Period

2 Answers2