how to parse a bin file by construct?

Question

the file format is:

from construct import *    

file_format=Struct(
        'n_links'/ Int32ul, # number of links
        'links'/ Array(this.n_links, Int32ul), # links
        'n_Items' / ???  # how to do here ? 
     )

02000000  0C000000  10000000  55000000          AA000000
n_links    link_0    link_1   value_of_link_0    value_of_link_1

how to parse 'n_Items' ?

score 0 · Accepted Answer · answered Jan 16 '19 at 08:04

I solved it:

file_format=Struct(
        'n_links'/ Int32ul, # number of links
        'links'/ Array(this.n_links, Int32ul), # links
        'n_Items' / Pointer(this.links[0], Int32ul[this.n_links])
     )
t=file_format.parse('\x02\x00\x00\x00\x04\x00\x00\x00\x08\x00\x00\x00') #ok parse

how to parse a bin file by construct?

1 Answers1