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I referred to this implementation in tensorflow. Itrequires the shape of the output batch embeddings but I can't get the actual shape of an mxnet symbol. Any ideas how?

swmeng
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1 Answers1

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You can use infer_shape() to get the shape of a symbol. For implementing triplet loss in MXNet you may want to check out this thread: https://github.com/apache/incubator-mxnet/issues/6909 Accordingly you can implement it the following way:

kernels = [(1, feature_size), (2, feature_size), (3, feature_size)]
for i in range(len(kernels)):
    conv_weight.append(mx.sym.Variable('conv' + str(i) + '_weight'))
    conv_bias.append(mx.sym.Variable('conv' + str(i) + '_bias'))

fa = get_conv(data=anchor,
              kernels=kernels, conv_weight=conv_weight, conv_bias=conv_bias,
              entity_weight=entity_weight, entity_bias=entity_bias,
              feature_name='fa')  # share weight.
fs = get_conv(data=same,
              kernels=kernels, conv_weight=conv_weight, conv_bias=conv_bias,
              entity_weight=entity_weight, entity_bias=entity_bias,
              feature_name='fs')
fd = get_conv(data=diff, 
              kernels=kernels, conv_weight=conv_weight, conv_bias=conv_bias,
              entity_weight=entity_weight, entity_bias=entity_bias,
              feature_name='fd') 

"""
triple-loss
"""
fs = fa - fs
fd = fa - fd
fs = fs * fs
fd = fd * fd
fs = mx.sym.sum(fs, axis=1, keepdims=1)
fd = mx.sym.sum(fd, axis=1, keepdims=1)
loss = fd - fs
loss = one - loss  # a scalar
loss = mx.sym.Activation(data=loss, act_type='relu')  # acts like a norm.
triple_loss = mx.sym.MakeLoss(loss) 
NRauschmayr
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