How to call $.dspBody() function in Mura without actually displaying the content?

Asked Dec 26 '18 at 23:36

Active Dec 27 '18 at 02:57

Viewed 115 times

I need to display the search results after a user searches. The results weren't showing so I went looking and according to this Google Group discussion, I needed to call the .dspBody() function.

I added that function to my template like so,

#$.dspBody(body='', title='',summary='', crumbList=false, showMetaImage=false)#

and then the search results started showing up right where I called that function.

However, the problem is that the content of the page is displayed further down the template using,

#$.content('title')#

#$.content('body')#

and so on. Therefore calling .dspBody() above where I want the search results to be results in the content being duplicated onto the page.

I reviewed the documentation for the function and didn't see an option for calling the functions without displaying the content.

Is there a way of calling .dspBody() so that no content appears?

edited Dec 27 '18 at 02:57

asked Dec 26 '18 at 23:36

Charlie Brumbaugh

3

Have you tried `` ? – James A Mohler Dec 27 '18 at 02:16
@JamesAMohler No, would I use that to substitute for the first or the second code blocks? – Charlie Brumbaugh Dec 27 '18 at 02:51
2

Try putting `#$.dspBody(body='', title='',summary='', crumbList=false, showMetaImage=false)#` and use `#bodyContent#` instead of `#$.content('body')#` – rrk Dec 27 '18 at 04:14
1

I was thinking what @RRK did – James A Mohler Dec 27 '18 at 04:54
@RRK I did that, but then I had extra content showing up where I called the `#bodyContent#` it was showing the page associated image in addition to the text – Charlie Brumbaugh Dec 27 '18 at 17:47

How to call $.dspBody() function in Mura without actually displaying the content?

0 Answers0