inputs: 'aa', '22', '2.45'
input ='22'
try:
print int(input)
except ValueError:
print float(input)
How to handle the above code when the input is 'aa' or 'example'?
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1another `try-except` inside your present `except` clause. – Ma0 Dec 18 '18 at 16:54
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decide what you want to do with inputs like that. ignore them? skip them? then write an if condition around it. – Paritosh Singh Dec 18 '18 at 16:54
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why not simply convert all value to float rather than int and float and wrap around try catch block – mad_ Dec 18 '18 at 17:03
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Thank you @Ev.Kounis --- It was easy and solved my problem.. – rmk_pyth Dec 18 '18 at 17:08
3 Answers
2
I think that the simplest way to handle this is to check if the input string is numeric first:
https://www.tutorialspoint.com/python/string_isnumeric.htm
if input.isnumeric():
print int(input)
else:
try
print float(input)
except ValueError:
# Do nothing
However if you can avoid exceptions completely the code would be better - exception handling can be quite expensive.
This answer to testing for an integer explains why exception handling can be expensive: https://stackoverflow.com/a/9859202/8358096
To avoid the second exception being hit regularly you could use the isalpha function mentioned below.
if input.isnumeric():
print int(input)
else:
if not input.isalpha():
try
print float(input)
except ValueError:
# Do nothing
L McClean
- 340
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0
s = 'aa'
try:
print int(s)
except ValueError:
try:
print float(s)
except:
print 'its is a string'
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2An explanation, what the posted code does and how this addresses the problem in the question, rarely fails to improve an answer. – MBT Dec 18 '18 at 19:41
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This code handle string. the previous code does not allow characters or string. – rmk_pyth Dec 18 '18 at 20:09
0
You should use str.isalpha
The only time this breaks in cases like input = 'a2'.
inputs = ['aa','22','2.45']
for input in inputs:
if not input.isalpha():
try:
print int(input)
except ValueError:
print float(input)
Levente Vig
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